OAB is a sector of the circle with centre O and radius 12 cms. If m∠AOB = 60°, find the difference between the areas of sectors AOB and ΔOAB.
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We have been given,
1) circle with centre O & radius 12 cm
2)sector AOB with ,AOB = 60 0
Area of sector AOB - area of sector OAB = (area of circle - area of sector OAB) - area of sector OAB
= area of circle - 2area of sector OAB

So, area of circle =πr2=π(12)2=452.39 cm2Area of sector OAB =θ360×πr2Where θ→angle subtended at centre of circle by arc r→Radius of the given circleArea of sector OAB =60360×452.39 cm2=452.39 cm26finally, difference of area =area of circle−2area of sector OAB =452.39 cm2 −2×452.39 cm26=(1−13)452.39 cm2=23×452.39 cm2 =301.60 cm2
1) circle with centre O & radius 12 cm
2)sector AOB with ,AOB = 60 0
Area of sector AOB - area of sector OAB = (area of circle - area of sector OAB) - area of sector OAB
= area of circle - 2area of sector OAB

So, area of circle =πr2=π(12)2=452.39 cm2Area of sector OAB =θ360×πr2Where θ→angle subtended at centre of circle by arc r→Radius of the given circleArea of sector OAB =60360×452.39 cm2=452.39 cm26finally, difference of area =area of circle−2area of sector OAB =452.39 cm2 −2×452.39 cm26=(1−13)452.39 cm2=23×452.39 cm2 =301.60 cm2
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