Question

OABC IS A SQUARE , O IS THE ORIGIN AND THE POINTS A AND B ARE ( 3,0 ) ( P, Q ) . IF OABC LIES IN THE FIRST QUADRANT , FIND THE VALUES OF P AND Q . ALSO WRITE DOWN THE EQUATION S OF AB AND BC

Answer 1

Answer:

P = 3  , Q = 3

AB   is x = 3

BC is  y = 3

Step-by-step explanation:

OA

O - 0 , 0

A - 3 , 0

Slope = (0-0)/(3 - 0) = 0

=> Line is Parallel to x axis

and as it passes through origin so

OA lies on x axis

OA = √(3-0)² +(0-0)² = 3

OABC is a square  

=> AB ║ y axis

& AB = 3

AB = √(P - 3)² + (Q - 0)²

=> √(P - 3)² + (Q - 0)² = 3

=> (P - 3)² + Q² = 9

line is parallel to y axis  =>   P = 3  

=> 0² + Q² = 9

=> Q = ±3

but it lies in 1st Quadrant so

Q = 3

P = 3  , Q = 3

AB   is x = 3

BC ||  OA

=> BC is at distnace of 3

=> BC is y = 3