Question

OABC is a square of side 7cm .If OAPC is a quadrant of a circle with centre O,then find the area of the shaded region .

Answer 1

hiii friend
here is your answer
as the side of the square is 7cm(OA)
and O is the centre of a quadrant
then the radius be 7cm
now are of the quadrant ⬇
$= \pi {r}^{2} \times .25 \\ = \frac{22}{7} \times 49 \times. 25\\ = 22 \times 7 \times .25 \\ = 154 \times .25 \\ = 38.5 {cm}^{2}$
now area of the quadrant =38.5cm^2
so, the left area=49cm^ -38.5cm^2
=10.5cm^2


glad to help you
hope it helps
thank you.

Answer 2

Answer: 38.5 $cm^2$ is the area of the shaded region

Given: We are given that OABC is a square of side 7 cm and OAPC is a quadrant of a circle with center O.

To Find: We need to find the area of the quadrant i.e., the area of the shaded region.

Step-by-Step Explanation: Firstly, we need to look at the formula for calculating the area of a circle:

Area of Circle = $\pi r^{2}$  

Therefore, Area of quadrant = $\pi \frac{r^{2}}{4}$

Step 1: I have attached the question figure with the solution. According to the figure:

Therefore, radius of the circle = 7cm

Area of shaded region = $\pi \frac{r^{2}}{4}$ = $\pi *\frac{7^{2}}{4}$ = $\frac{22}{7}*7*7*\frac{1}{4}$ = $\frac{77}{4}$ = 38.5 $cm^{2}$

To know more about the topic circles, refer to the links below:

https://brainly.in/question/9487448

https://brainly.in/question/7424751

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