Chemistry, asked by praveenkuchanna, 9 months ago

OB' value in the above diagram​

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Answered by Atαrαh
1

 \frac{1}{f}  =  (\frac{nl}{nm}  - 1)( \frac{1}{r1}  -  \frac{1}{r2} )

nl/nm=3/2(1)-1=1/2

r1=-36cm

r2=36cm

 \frac{1}{f}  = ( \frac{1}{2} )(  \frac{ - 2}{36}  )\\ f =  - 36cm

u=-60cm

 \frac{1}{f}  =  \frac{1}{v}  -  \frac{1}{u}  \\  \frac{1}{ - 36}  -  \frac{1}{60}  =  \frac{1}{v}   \\  \frac{1}{v}  =  \frac{96}{ -2160 }   \\ v =  - 22.5cm

i hope this helps ( ╹▽╹ )

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