Question

Object A has double the Kinetic energy as that possessed by object B. The linear momenta of A and B are in ratio 3 : 2. What is the ratio of mass of A and B?

Answer 1

Answer:

hope this to be enough,

can't get better solution.

Answer 2

Given:

The ratio of K.E, K1 = 2 K2

The ratio of Linear Momenta, P1 : P2 = 3 : 2

To Find:

The ratio of mass of A and B.

Calculation:

- It is given that:

K1 = 2 K2

⇒ 1/2 × m1 × v1² = 2 × 1/2 × m2 × v2²  

⇒ m1 × v1² / m2 × v2² = 2  

⇒ m1 × v1 / m2 × v2 = 2 × v2/v1     ....(i)

⇒ P1/P2 = 2 × v2/v1

⇒ 3/2 = 2 × v2/v1

⇒ v1/v2 = 4/3

- Putting this in equation (i), we get:

m1/m2 × 4/3 = 2 × 3/4

⇒ m1/m2 = 18/16

⇒ m1/m2 = 9/8

- So the ratio of mass of A and B is 9/8.