Question

Object b is traveling with a speed of 8m/s and with acceleration of 5m/s^2 followed by object a moving with velocity 10m/s if the distance between object a and b is 100m then what should be the acceleration of object a to overtake b in 20 seconds.​

Answer 1

Answer:

Distance traveled by car A=S

A

Distance traveled by car B=S

B

According to formula S=ut+

2

1

at

2

S

A

=0t+

2

1

×2t

2

S

B

=10t+

2

1

×0t

2

Car A will overtake car B when

S

A

=S

B

+100

Putting the value S

A

and S

B

+2=10t+100

+2−10t−100=0

After solving for t, we get

t=16.18sec possible

t=−6.10sec not possible