Question

Object displaced from 5 m height reaches ground at a distance of 10m. What is its
final velocity?
10 m/s
10 V2 m/s
29 m/s
20 V2 m/s
​

Answer 1

Answer:

10m/s

Explanation:

$\\ range \: = u \sqrt{2h \div g}$

10=u

Answer 2

Answer:

Final velocity u = 10$\frac{m}{s}$

Step-by-step Explanation:

According to this question

We have given that

Height h = 5 m, Distance(range) = 10 m

The final velocity is the last velocity of a given object after a period of time.

Formula, Range = $u\times \sqrt\frac{2h}{g}$

                      10 = $u\times \sqrt\frac{2\times 5}{10}$

                       u = 10$\frac{m}{s}$

Hence, value of final velocity  u = 10$\frac{m}{s}$