Object is beyond c of a concave mirror magnification in this case is ( ). A) -1<m<0 B). -1. C)0<m<1. D) +1
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Answer:
Option(A) -1<m<0
Step-by-step explanation:
Let distance of object from pole be U, distance of image from pole be V, focal distance be f, c be the centre of curvature and m be its magnification.
w.k.t., magnification of mirror, m = -v/u = -(-V)/(-U) = -V/U
Also, since the object is placed beyond c of the concave mirror. Therefore, the image is formed between f and c.
⇒ U>2f and f<V<2f
⇒ m will be less than 1 in magnitude.
Also, m is negative.
∴ -1<m<0
So, option(A) is correct.
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