Math, asked by rpmartinez, 1 year ago

Object is dropped 44ft below the tip of the pinnacle atop a 368ft tall building. The height h of the object after t seconds is given by the equation h=-16t squared+324. Find how many seconds pass before the object reaches the ground

Answers

Answered by Anonymous
1
show the height of the object when it was dropped is equal to 368 - 44 =324 ft
so given 324 =-16t²+324
0=-16t²
t=0

Anonymous: mark me as brain list please
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