Question

Object is dropped from rest. It covers s1 distance in first second and s2 distance in next second. Find ratio of s2 to s1

Answer 1

Answer: 2:1

Step-by-step explanation:

Let u be the initial velocity and v be final velocity

According to 2nd equation of motion

S = u + gt

S1 = 0 + 10 × 1

S1 = 10 m

Taking time as 2 seconds

S2 = u + gt

S2 = 0 + 10 × 2

S2 = 20 m.

So,

Ration = S2/S1

= 20/10

= 2:1

Hope it helps