Physics, asked by ankit37727, 7 months ago

Object is falling down with a speed of 30m/s. After 3 seconds its velocity will be ? (g=10m/s2)​

Answers

Answered by Anonymous
104

{\mathfrak{\underline{\purple{\:\:\: Given:-\:\:\:}}}} \\ \\

\:\:\:\:\bullet\:\:\:\sf{Initial\: velocity\: (u) \:= \:30m/s}

\:\:\:\:\bullet\:\:\:\sf{Time \ taken \ (t) \ = \ 3 s}

\:\:\:\:\bullet\:\:\:\sf{Acceleration \ (a) \ = \ 10m/s^{2}}

\\

{\mathfrak{\underline{\purple{\:\:\:To \:Find:-\:\:\:}}}} \\ \\

\:\:\:\:\bullet\:\:\:\sf{Final \ velocity \ (v)}

\\

{\mathfrak{\underline{\purple{\:\:\: Solution:-\:\:\:}}}} \\ \\

{\sf{\underline{\:\:\:By \ using \ 1st \  equation \ of \ motion\:\:\:}}}

\\

\dashrightarrow\:\: \sf{v = u+at}

\\

\dashrightarrow\:\: \sf{ v = 30 + 10\times 3}

\\

\dashrightarrow\:\: \sf{ v = 30 + 30}

\\

\dashrightarrow\:\: \sf{ v = 60m/s}

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\therefore\:\:{\underline{\sf{ \: Final\: velocity\:  of \:the \:object \:is \:60m/s\:}}}

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{\mathfrak{\underline{\purple{\:\:\:Additional \:Information:-\:\:\:}}}} \\ \\

\star\:\sf{Some\:equation\: of \:motion }

\boxed{</p><p></p><p>\begin{minipage}{3 cm}$\\</p><p></p><p>\sf{\:\bullet\:\:v = u +at} \\ \\</p><p></p><p>\sf{\:\bullet\:\:s = ut + \frac{1}{2}\:at^{2} }\\ \\</p><p></p><p>\sf{\:\bullet\:\:v^{2} = u^{2} + 2as}\\$</p><p></p><p>\end{minipage}</p><p></p><p>}

\sf{Where,}

\:\:\:\:\bullet\:\:\:\textsf{v = Final velocity}

\:\:\:\:\bullet\:\:\:\textsf{u = Initial velocity}

\:\:\:\:\bullet\:\:\:\textsf{a = Acceleration}

\:\:\:\:\bullet\:\:\:\textsf{s = Distance}

\:\:\:\:\bullet\:\:\:\textsf{t = Time taken}

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