object is falling freely from a tower it travels distance =1/2 the height of the tower in its last second of journey
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Answer:
Explanation:
Time of flight =
g
2H
s
Distance traveled in last second =H-distance traveled in =(
g
2H
−1)s
Distance traveld in (
g
2H
−1)s=
2
1
g(
g
2H
−1)
2
=
2
g
[
g
2H
+1−2
g
2H
]
=H+
2
g
−g
g
2H
=H+
2
g
−g
2H
g
15=H−(H+
2
g
−
2gH
=
2gH
−
2
g
=
2gH
−5
2gH
=20
2×10×H=400
H=20m
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