Object of height 4cm is placed in front of a concave lens of power 10d.find the size of the image. (v=-6; h’=2. 4
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Answer:
given
h = 4 cm
u = 15 cm
p = -10 D
we know that
P = 100\f( in cm)
-10 = 100\f
therefore f = -10 cm
1\v - 1\u = 1\f
1\v - 1\15 = 1\-10
v = -6 cm
h'\h = v\u
h' = -6\-15*4
h' = 1.6 cm
therefore object height is 1.6 cm.
Explanation:
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