Question

Object of height 8cm is placed at 50 cm in front of a concave mirror of focal length 30 . At what distance from mirror should a screen be placed in order to obtain a sharp image ? Also find the nature and size of image

Answer 1

Answer:

Explanation:

given , object height= 8cm

focal length of concave mirror (f)= (-30cm)

object distance (u) = (-50cm)

1/f=1/u + 1/v

= 1/f - 1/u = 1/v

= 1/(-30) - 1/(-50) = 1/v

= -1/30 - (-1/50) = 1/v

= -1/30 + 1/50 = 1/v

= (-5+3)/150 = 1/v

-2/150 = 1/v

-1/75 = 1/v

v=(-75) cm

therefore screen must be placed at 75 cm in front of mirror for a sharp image. the image is real and inverted.

now ,  image height / object height = -v/u

= image height / 8 = -(-75)/-50

= image height / 8  = -3/2

= image height = (-3 x 8)/2

=image height = -12 cm

therefore , the image is 12 cm in size , real and inverted.

Answer 2

Answer:

I hope it is help's you

Explanation:

Mark me has a brainlist