object of mass 10 kg is moving with a velocity of 10 metre per second a force of 50 Newton acted upon for 2 second percentage increase in its kinetic energy ok
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Since it is acted upon simultaneously by two forces 4N and 3N at right angles, net force =42+32
=5N
The mass is given as 10Kg→a=mF=105=0.5s2m
we calculate the kinetic energy K.E=21mv2=21m(at)2
KE=2110×0.52×10s=125J
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