Question

object of mass 2kg is at rest on surface a force of 10n acts on it for 10 seconds calculate the distance travelled by the body​

Answer 1

Answer:

Given: F=10 N,m=2 kg,t=3s, Initial velocity, u=0

Step 1: Acceleration of the body

F=ma

⇒a=

m

F

=

2 Kg

10 N

=5m/s

2

Step 2: Velocity acquired by the body after 3s

As acceleration is constant, therefore applying equation of motion:

v=u+at=0+5×3=15m/s

Step 3: Change in momentum

Change in momentum = Final momentum − Initial momentum

=mv−mu=m(v−u)

=2kg (15 m/s−0)

=30 kg-m/s

Answer 2

Answer:

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