Physics, asked by johnnzangi, 5 months ago

object
The gravitational potential Energy of an
of mass m at a height h above
the surface of the earth is equal to GMEM
show that it is consistent with the
expression
'mgoh' for gravitational potential
Chergy where go is the acceleration due
to gravity on the surface of the earth.
(​

Answers

Answered by SAMYAKMAHINDRAKAR
0

Answer:

If a point mass m is placed at a height h from surface of earth, the potential energy is

U

h

=−

(R+h)

GMm

=

R(1+

R

h

)

−gR

2

m

=

R

−gR

2

m

(1+

R

h

)

−1

(∵g=

R

2

GM

)

U

h

=

R

2

−gR

2

m(R−h)

=−gm(R−h)

⇒V=

m

U

h

=

m

−gm(R−h)

=−g(R−h)

Answered by ankitaggarwal26
0

Answer:

object

The gravitational potential Energy of an

of mass m at a height h above

the surface of the earth is equal to GMEM

show that it is consistent with the

expression

'mgoh' for gravitational potential

Chergy where go is the acceleration due

to gravity on the surface of the earth.

(

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