Question

object the relation for the distance travelled by an object moving with a uniform acceleration in the interval between 4th and 5th seconds

Answer 1

Uniform acceleration in the interval between 4th and 5th seconds =

= (5u + 1/2 * a * 5^2) - (4u + 1/2 * a * 4^2)

= 5u + 1/2 *a * 25 - 4u + 1/2 * a * 16

= u + 1/2 * a * (25-16)

= u + 1/2 * a * 9

= u + 9/2 * a

If it starts from rest then the displacement will be 9/2a.

Answer 2

Answer:

thuhhfzseryeq1346tgjok cgxeaadyhmoyedcgr6u

Explanation:

hujhdhvgr357ytwasgjk