Question

Object travels 18m 3s and then another 10m 2s.what is the average speed of the object?

Answer 1

Appropriate Question:

An object travels 18m in 3s and then another 10m in 2s. What is the average speed of the object?

Answer:

5.6 m/s

Explanation:

As per the provided information in the given question, we have :

• An object travels 18m in 3s and then another 10m in 2s.

We are asked to calculate the average speed of the object.

Average speed of the object is defined as total distance travelled divided by total time. Mathematically,

$\longmapsto \rm { Speed_{(avg)} = \dfrac{Total \; distance}{Total \; time} }$

Now, according to the question in first time it covers 18 m in 3 seconds and then in next time it covers 10 m in 2 seconds.

$\longmapsto \rm { Speed_{(avg)} = \dfrac{S_1 + S_2 }{T_1 + T_2 } }$

Substituting the values.

$\longmapsto \rm { Speed_{(avg)} = \dfrac{(18 + 10)\; m }{(3 + 2)\; s } }$

Performing addition.

$\longmapsto \rm { Speed_{(avg)} = \dfrac{28 \; m }{5 \; s } }$

$\longmapsto \bf { Speed_{(avg)} = 5.6 \; ms^{-1} }$

∴ Average speed of the object is 5.6 m/s.

Answer 2

Answer:-

Distances travelled by object.

1. 18m
2. 10m

Time taken by object

1. 3s
2. 2s

We know that

$\boxed{\sf Average\:Speed=\dfrac{Total\:Distance}{Total\;Time}}$

$\\ \sf \longmapsto Average\:Speed=\dfrac{18m+10m}{3s+2s}$

$\\ \sf \longmapsto Average\:Speed=\dfrac{28m}{5s}$

$\\ \sf \longmapsto Average\:speed=5.6m/s$