Math, asked by aarushiagrawal2425, 4 months ago

Observation
1. Total number of possible outcomes
2. Total number of favourable outcomes of sum 2
3. Total number of favourable outcomes of sum 3
4. Total number of favourable outcomes of sum 4
5. Total number of favourable outcomes of sum 5 =
6. Total number of favourable outcomes of sum 6 =
7. Total number of favourable outcomes of sum 7 =
8. Total number of favourable outcomes of sum 8 =
9. Total number of favourable outcomes of sum 9 =
10. Total number of favourable outcomes of sum 10
11. Total number of favourable outcomes of sum 11
12. Total number of favourable outcomes of sum 12 =
13. Total number of favourable outcomes (sum 9) =
14. Total number of favourable outcomes (sum < 5) =
15. Total number of favourable outcomes (both the number are prime) =
Lab Manual in Mathematics-X 61​

Answers

Answered by mathdude500
23

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Answer:

When two dices are thrown :-

Step-by-step explanation:

Observation

1. Total number of possible outcomes = 36

2. Total number of favourable outcomes of sum 2 = 1

3. Total number of favourable outcomes of sum 3 = 2

4. Total number of favourable outcomes of sum 4 = 3

5. Total number of favourable outcomes of sum 5 = 4

6. Total number of favourable outcomes of sum 6 = 5

7. Total number of favourable outcomes of sum 7 = 6

8. Total number of favourable outcomes of sum 8 = 5

9. Total number of favourable outcomes of sum 9 = 4

10. Total number of favourable outcomes of sum 10 = 3

11. Total number of favourable outcomes of sum 11 =2

12. Total number of favourable outcomes of sum 12 = 1

13. Total number of favourable outcomes (sum 9) = 4

14. Total number of favourable outcomes (sum < 5) = 6

15. Total number of favourable outcomes (both the number are prime) = 8

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Answered by mangersara425
0

Answer:

total numbr of favourable outcomes of sum 5

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