Question

OBSERVATIONS

Mass of 50 mL distilled water (assuming density as 1g /cc) = 50.0 g
Mass of BaCl2.H20 = 3.6 g
Mass of BaCl2 solution = 53.6 g
Mass of Na2SO4.10H2O = 8.05 g
Mass of Na2SO4 solution =58.05 g
Total mass of reactants (solutions of BaCl2 and Na2SO4) = 53.6 + 58.05 = 111.65 g
Mass of empty 150 mL beaker,m1 =………………….g
Mass of reaction mixture before precipitation, m2= m1+ 111.65 g = ……………………g
Final mass of reaction mixture after precipitation, m3 =……………………. g​

Answer 1

M3=1000 g

Explanation:

m3=1000g

M2=M1+1111.95g=2000