observe circuit given below calculate equivalent resistance if cell provides voltage of 2V ? find total current and reading shown by voltmeter..
Diagram is not sent
but;
There is one two ohm resistor in series. and ammeter in series. and 4 ohm resistor (both) in parallel and a voltmeter is also there in parallel.
and there is a battery and a key..
PLZ PLZ SOLVE URGENTLY
NEED VERY URGENT..
THANKU MATE..
Answers
Given :
Cell of voltage 2V is connected in circuit .
An ammeter is connected in series
One Two ohm resistor is connected in series
A 4 ohm resistance is connected in parallel & voltmeter is connected in parallel
To Find :
Value of equivalent resistance & current in ammeter & voltage in voltmeter .
Solution :
•A two ohm resistance & 4 ohm resistance is connected in parallel
•Req = 1/R1 + 1/R2
Req = 1/2 + 1/4
Req = 2/4 + 1/4:
Req = 3/4
Req = 4/3 ohms
•Current in ammeter
R(equivalent) = 4/3 ohms
Voltage = 2V
Current = 2/(4/3)
current = 6/4
current = 3V/2 Ampere
•Now Current in 4 ohm resistor will be I = 3V/2 [ 2/(2+4)]
I = 3V/2(2/6)
I = V/2 Ampere
•Value of voltage by voltmeter
Since , voltmeter is connected across 4 ohm resistance so it will measure voltage around 4 ohms resistor
hence , voltage = IR
Voltage = IR
Voltage = (V/2)*4
Voltage = 2V