observe Circuit. The power consumed by register
R2 is P. The power consumed by resistor
R1 when resistance R is removed from the circuit is ______ take R1 =R2
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Answer:
Explanation:total resistance is 1/R1+1/R2
=2/R
V=IR HERE R=2/R SO
V=I×2/R
I=2V/R
IN SECOND CASE THERE IS ONLY ONE RESISTER SO
I=VR
NOW,
POWER IN FIRST CASE IS
P=IV
P=(2V/R)×V (I=2V/R)
P=2V^2/R
P=》》2(V^2/R)《《
POWER IN FIRST CASE IS
P=IV
》》P=(V^2/R)《《
IT MEANS POWER CONSUPTION
REDUCED TO HALF WHEN ONE OF THE RESISTER IS REMOVED
Sorry that i can't exapin you well as i have very less time
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