Observe the circuit diagram given below, find the error and redraw the correct diagram.
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Explanation:
When 8 and 12 are in parallel
and 7.2 is in series with them
Net Resistance $$ \dfrac { 7.2 }{ 10 } +\dfrac { 8\times 12 }{ 12+8 } $$
$$=\dfrac { 72 }{ 10 } +\dfrac { 96 }{ 20 } \\ =\dfrac { 72 }{ 10 } +\dfrac { 48 }{ 20 } \\ =\dfrac { 120 }{ 10 } \\ =12\Omega $$
Total current $$=\dfrac { V }{ netR } =\dfrac { 6 }{ 12 } =0.5\Omega $$
Voltage across $${ R }_{ 1 }=i{ R }_{ 1 }\\ =0.5\times 7.2\\ =3.6$$
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