Observe the circuit given and find the resistance across AB.
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Answered by
2
1/R1= 1/1+1/1=2
R1=1/2
R=R1+R1
R= 1/2 + 1/2 = 1
R1=1/2
R=R1+R1
R= 1/2 + 1/2 = 1
Answered by
1
Answer:
Resistance across AB = 1 Ω
Explanation:
Pair of Two 1 Ω resistance in Parallel is in series
first we find resistance of
two Parallel 1 Ω Resiatance
1/R = 1/1 + 1/1
=> 1/R = 1 + 1
=> 1/R = 2
=> R = 1/2 Ω
Similarly other two parallel 1 Ω Resistirs resistnce
would be 1/2 Ω
Now these Resistances are in series
net effective resistance
Reff = 1/2 + 1/2
=> Reff = (1 + 1)/2
=> Reff = 2/2
=> Reff = 1
Resistance across AB = 1 Ω
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