Physics, asked by anujgeraANUJ3005, 1 year ago

Observe the circuit given and find the resistance across AB.

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Answers

Answered by 4TSuccess
2
1/R1= 1/1+1/1=2
R1=1/2
R=R1+R1
R= 1/2 + 1/2 = 1
Answered by amitnrw
1

Answer:

Resistance across AB = 1 Ω

Explanation:

Pair of Two 1 Ω  resistance in Parallel is in series

first we find resistance of

two Parallel 1 Ω Resiatance

1/R = 1/1 + 1/1

=> 1/R = 1 + 1

=> 1/R = 2

=> R = 1/2 Ω

Similarly other two parallel 1 Ω Resistirs resistnce

would be  1/2 Ω

Now these Resistances are in series

net effective resistance

Reff = 1/2  + 1/2

=> Reff = (1 + 1)/2

=> Reff = 2/2

=> Reff = 1

Resistance across AB = 1 Ω

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