Question

Observe the data in the following table
Material
Refractive index
Ice
1.31
Water
1.33
Benzene
1.5
Carbondisulphide 1.63
Depending on the above values,
i) Find out the material in which light travel with less velocity?
ii) Find out the speed of light in benzene?
iii) Find out the material in which light travel with greater velocity among the given ?
iv) Find out the refractive index of benzene with respect to water?
v) Find out the refractive index of air with respect to benzene?​

Answer 1

Answer:

1. Carbon disulphide
2. 2*10⁸ m/s.
3. ice
4. 1.12
5. 0.667

Explanation:

1. The speed of light decreases with an increase in refractive index. Since among the following carbon disulphide has the highest refractive index, the light will travel with minimum velocity.

2. We know that,

$n=c/v$ (c =3*10⁸ m/s; n=1.5)

∴ v = c/n = 2*10⁸ m/s

The speed of light in benzene is 2*10⁸ m/s.

3. Light will have the greatest velocity in ice due to its lowest refractive index.

4.  The refractive index of benzene with respect to water = 1.5/1.33=1.12

5. The refractive index of air with respect to benzene = 1/1.5 =0.667

Answer 2

Answer:

1. Carbon disulphide
2. 2*10⁸ m/s.
3. ice
4. 1.12
5. 0.667

Explanation:

1. The speed of light decreases with an increase in refractive index. Since among the following carbon disulphide has the highest refractive index, the light will travel with minimum velocity.

2. We know that,

$n=\frac{c}{v}$ $(c =3*10^{8} m/s; n=1.5)$

∴$v = \frac{c}{n} = 2*10^{8} m/s$

The speed of light in benzene is $2*10^{8} m/s.$

3. Light will have the greatest velocity in ice due to its lowest refractive index.

$Refractive index=\frac{velocity of light in air}{velocity of light in medium}$

velocity of light in medium is inversly praportional to velocity of light in air

so,velocity order is $Ice > Water > Bronze > Carbondisulphide$

4.  The refractive index of benzene with respect to water  $\frac{1.5}{1.33}\\=1.12$

5. The refractive index of air with respect to benzene $=\frac{1}{1.5}$  $=0.667$

The project code is #SPJ3