Question

Observe the figure and complete the following activity.

In  ABC and  EDC,

0 ABC  - (Each measures 46 )

C  C - ( )

ABC   - ( test for similarity)​

Answer 1

Complete Activity :-

→ ABC = ∠EDC { Each measure 46° }

→ ∠C = ∠C { common }

→ ∆ABC ~ ∆EDC { By AA test for similarity }

Complete Question :- Refer to image .

Concept used :-

• If two pairs of corresponding angles of two triangles are congruent, then the triangles are similar by AA similarity .

Solution :-

from image we can see that in ∆ABC and ∆EDC, we have,

→ ∠ABC = ∠EDC { Each measure 46° }

→ ∠C = ∠C { common }

So,

→ ∆ABC ~ ∆EDC { By AA test for similarity }

Extra knowledge :- When two triangles are similar, their corresponding sides are in same proportion .

since,

→ ∆ABC ~ ∆EDC

So,

→ AB/ED = BC/DC = AC/EC .

Learn more :-

In the figure along side, BP and CP are the angular bisectors of the exterior angles BCD and CBE of triangle ABC. Prove ∠BOC = 90° - (1/2)∠A .

https://brainly.in/question/32333207

Answer 2

Answer:

InABC andEDC,

Angle ABC congruent Angle EDC..... (Each measures 46° )

Angle C congruent to Angle C..... (Common sides)

ThereforeABC similar toEDC...... (AA test for similarity)