Question

observe the figure and write the value of sin x and tan x​

Answer 1

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Answer 2

THE VALUE OF THE FOLLOWING IS :-

sinx =  $\frac{P}{H}$ = $\frac{PQ}{PR\\}$ = $\frac{6}{12}$ = $\frac{1}{2}$

tanx = $\frac{P}{B}$ = $\frac{PQ}{QR}$ = $\frac{6}{x}$

By using pythagoras theorem:-

$QR^{2}$ =  $PQ^{2}$ - $PR^{2}$

$QR^{2}$ = $12^{2}$ - $6^{2}$

$QR^{2}$ = 144 - 36

QR = $\sqrt{118}$

tanx =  $\frac{P}{B}$ = $\frac{PQ}{QR}$ = $\frac{6}{\sqrt{118} }$

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