Observe the flow-chart of a monohybrid cross in a clitoria plant and write the answers
for A, B, C, D:
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A=Bb and Bb
B=Bb. Bb
C=Blue flower: white flower=3:1
D=BB:Bb:bb=1:2:1
B=Bb. Bb
C=Blue flower: white flower=3:1
D=BB:Bb:bb=1:2:1
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Flow-chart of a mono hybrid cross in a clitoria plant
- When two parent, one with genotype "BB" is crossed with other another genotype "bb", it leads to the production of progeny with allele "Bb" in F1 generation. Thus A is "Bb"
- When the F1 generation gametes are self crossed with parent "B" and "b", it leads to the formation of "BB", "Bb", "Bb" and "bb". Thus B is "Bb".
- The phenotype ratio of the given cross is 3:1, which is nothing but 3 blue flowers and 1 white flower. Thus C is 3:1.
- The genotypic ratio is 1:2:1, which means 1 "BB", 2 "Bb", and 1 "bb". Thus D is 1:2:1.
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