Observe the following figure which bulb get fuse.
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This question tests on the relationship between, power, current and voltage.
The formula connecting the three is as follows :
P = VI
P = Power in watts
V = Voltage in Volts.
I = Current in Amperes.
Given the voltage and power we can get the current.
We get them as follows :
1) 220V, 100W
I = 100/220 = 0.4545 A
2) 220 V, 50 W
I = 50/220 = 0.227 A
Given that the bulb with 50 W and 220 V has a lower current carrying capacity than the bulb having 100W and 220 V it will require a fuse so that it is not blown by the excess current from the bulb rated at 100 W.
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