Question

Observe the given circuit :
2Ω
4Ω
4Ω
6 V
WITH
wums
5 Ω
Calculate the total resistance in the circuit and the total current flowing in
the circuit.​

Answer 1

Answer:

R = 6 ohm    I = 1 A

Explanation:

1 / R = 1/2 + 1/4 + 1/4

1/R = 1       --> R = 1

R =  1 + 5   =   6 ohm

V = IR

I = V/ R

 = 6/6

I = 1 A

Answer 2

Answer

Req = 6 Ω

Current = 1 A

Given

A circuit having 4 resistances 2Ω , 4Ω , 4Ω are connected in parallel with each other and theses three are connected in series with 5Ω

To Find

Equivalent resistance

Total current flowing in the circuit

Point's to be noted

When resistance R1,R2,R3,.... Rn are connected in series ,

→ Req = R1 + R2 + R3 + ..... + Rn

When resistances R1,R2,R3,...,Rn are connected in parallel ,

→ Req = 1/R1 + 1/R2 + 1/R3 + .... + 1/Rn

Ohm's Law

→ V = IR

Solution

Let us assume R₁ = 2Ω , R₂ = 4Ω , R₃ = 4Ω and R₄ = 5Ω

Now , R₁ , R₂ and R₃ are connected in parallel

⇒ 1 / R₁₂₃ = 1 / R₁+ 1 / R₂ + 1 / R₃

⇒ 1 / R₁₂₃ = 1/2 + 1/4 + 1/4

⇒ R₁₂₃ = 1 Ω

R₁ , R₂ and R₃ are connected in series with R₄

⇒  Req =  R₁₂₃ +  R₄

⇒  Req = 1  + 5

⇒  Req = 6 Ω

⇒ Req = 6 Ω

Potential difference , V = 6 V

Current , I = ? A

Apply Ohm's Law ,

⇒ V = IR

⇒ 6 = I (6)

⇒ I = 1 A