Question

Observe the given figure and answer the following questions .

a) the time period of a simple pendulum is the time taken by it to travel from ?

b) Time taken by the bob to move from A to C if t_1 and from C to O is t_2 . The time period of the simple pendulum is ____ .

Answer 1

Answer:

The time period of a simple pendulum: It is defined as the time taken by the pendulum to finish one full oscillation and is denoted by “T”. The amplitude of simple pendulum: It is defined as the distance travelled by the pendulum from the equilibrium position to one side

A pendulum of length will take how long to complete one period of its swing? Roughly 6.3 seconds is the time it takes for the pendulum to complete one period

Explanation:

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Answer 2

Observe the given figure and answer the following questions .

a) the time period of a simple pendulum is the time taken by it to travel from ?

b) Time taken by the bob to move from A to C if $\sf t_1$ and from C to O is $\sf t_2$ . The time period of the simple pendulum is ____ .

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$\: \: \boxed{\boxed{\bf{\mapsto \: \: \:Question \: 1 :-}}}$

a) the time period of a simple pendulum is the time taken by it to travel from ?

$\: \: \boxed{\boxed{\bf{\mapsto \: \: \:Solution :-}}}$

the time period of a simple pendulum is the time taken by it to travel from A to B and back to A

$\: \: \boxed{\boxed{\bf{\mapsto \: \: \:Question \: 2:-}}}$

Time taken by the bob to move from A to C if $\sf t_1$ and from C to O is $\sf t_2$ . The time period of the simple pendulum is ____ .

$\: \: \boxed{\boxed{\bf{\mapsto \: \: \: Solution}}}$

Given,

» Time taken to move from A to C = $\sf t_1$

» Time taken to move from C to O = $\sf t_2$

To find ,

» time period of the simple pendulum

~ Let's solve it ,

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We know that

$\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\\\;\large{\boxed{\sf{ time \: period \: = \frac{total \: time \: taken}{no. \: of \: oscillation} }}}\end{gathered}\end{gathered} \end{gathered}\end{gathered}$

So ,

• Total time taken = $\sf t_1$ + $\sf t_2$

• No. of oscillation = ¼

~ Let's put the value..

$\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\\\;\large{ \longrightarrow{\sf{ time \: period \: = \dfrac{t_1+ t_2}{ \dfrac{1}{4} } }}}\end{gathered}\end{gathered} \end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\\\;\large{ \longrightarrow{\sf{ time \: period \: = 4({t_1+ t_2}) }}}\end{gathered}\end{gathered} \end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\\\;\large{ \longrightarrow{\sf{ time \: period \: = 4{t_1+ 4t_2} }}}\end{gathered}\end{gathered} \end{gathered}\end{gathered}$

$\: \: \boxed{\boxed{\bf{\mapsto \: \: \: Hence, \: total \: time \: period \: \: \underline{\underline{4t_1+4t_2}}}}}$