Question

Observe the given graph and answer the questions that follow.
a) Find out the acceleration of the moving object in the first 4 seconds.
b) Calculate acceleration of moving object from the gap 12 sec to 16
sec.
c) What is the distance travelled by the object from 16 to 20 sec.

Answer 1

Answer:

Explanation:

a) Acceleration= Slope of v-t graph

                       = 5/4 m/s^2

b) From 12 sec to 15 sec velocity remains constant(uniform motion)

Therefore, acceleration = 0

c) Distance travelled= Area under v-t graph

= 4 * 5 = 20 m

Answer 2

Explanation:

A) 1.25 m/s²

B)0.3125m/s²