Math, asked by khadyeaditi6066, 1 year ago

Observe the measures of pots in figure 7.8 and 7.9. How many jugs of water can the cylindrical pot hold ?

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Answers

Answered by tiwaavi
66

In the figure 7.9,

Radius of the cylindrical pot = 7 cm.

Height of the Pot = 10 cm.


∴ Volume of the cylindrical Pot = πr²h

= 22/7 × 7 × 7 × 10

= 220 × 7

= 1540 cm³


Thus, the amount of the water than Cylindrical Pot can holds is 1540 cm³.


From the Figure 7.8,

Radius of the Conical jug = 3.5 cm.

Height of the Jug = 10 cm.


∴ Volume of the water than 1 Jug can holds = 1/3 × 22/7 × 3.5 × 3.5 × 10

= 385/3 cm³.



Now, Number of Jugs of water that is required to fill the cylindrical pot = 1540/(385/3)

= 4 × 3

= 12



Hence, the answer is 12.



Hope it helps.

Answered by mysticd
23

Hi ,


1 ) Dimensions of the conical jug :


Radius of the jug = r = 3.5 cm


Height ( h ) = 10 cm


volume of the jug = V1 = ( πr²h )/3


2 ) Dimensions of the Cylindrical water pot :


Radius ( R ) = 7 cm


Height ( H ) = 10 cm


Volume of the pot ( V2 ) = πR²H


Let number of jugs of water pot hold = n


n = V2/V1


n = ( πR²H )/( πr²h/3 )


n = ( 3R²H )/( r²h )


n = ( 3 × 7 × 7 × 10 )/( 3.5 × 3.5 × 10 )


n = 12


∴ Number of jugs of water Pot hold = n = 12


I hope this helps you.


: )

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