Observe the measures of pots in figure 7.8 and 7.9. How many jugs of water can the cylindrical pot hold ?
Answers
In the figure 7.9,
Radius of the cylindrical pot = 7 cm.
Height of the Pot = 10 cm.
∴ Volume of the cylindrical Pot = πr²h
= 22/7 × 7 × 7 × 10
= 220 × 7
= 1540 cm³
Thus, the amount of the water than Cylindrical Pot can holds is 1540 cm³.
From the Figure 7.8,
Radius of the Conical jug = 3.5 cm.
Height of the Jug = 10 cm.
∴ Volume of the water than 1 Jug can holds = 1/3 × 22/7 × 3.5 × 3.5 × 10
= 385/3 cm³.
Now, Number of Jugs of water that is required to fill the cylindrical pot = 1540/(385/3)
= 4 × 3
= 12
Hence, the answer is 12.
Hope it helps.
Hi ,
1 ) Dimensions of the conical jug :
Radius of the jug = r = 3.5 cm
Height ( h ) = 10 cm
volume of the jug = V1 = ( πr²h )/3
2 ) Dimensions of the Cylindrical water pot :
Radius ( R ) = 7 cm
Height ( H ) = 10 cm
Volume of the pot ( V2 ) = πR²H
Let number of jugs of water pot hold = n
n = V2/V1
n = ( πR²H )/( πr²h/3 )
n = ( 3R²H )/( r²h )
n = ( 3 × 7 × 7 × 10 )/( 3.5 × 3.5 × 10 )
n = 12
∴ Number of jugs of water Pot hold = n = 12
I hope this helps you.
: )