Question

Observe the measures of pots in figure 7.8 and 7.9 .how many jugs of water can the cylindrical pot hold?

Answer 1

Answer:

12 jugs of water

Step-by-step explanation:

Cylindrical pot:

R=7 cm, H=10 cm

V= pie * R^2 * H = pie* 7*7*10= 490 pie

Conical jug:

r= 3.5 cm, h=10 cm

v=1/3 * pie * r^2 * h = (pie * 3.5 * 3.5 * 10)/3 = (122.5 pie)/3

no. of jugs of water= V of cylindrical pot/ v of conical jug

                                 = (490 pie)/(122.5 pie)/3            [pie gets cancel]

                                 =4900*3/1225 = 14700/1225= 12