Question

*Observe the quadratic equation, x² − 2√3x + 3 = 0. Find the value of b² − 4ac.*

1️⃣ 0
2️⃣ −5
3️⃣ 12
4️⃣ 24​

Answer 1

Answer:

Option 1) 0

Step-by-step explanation:

In x²-2√3+3 ,

a = 1

b = -2√3

c = 3

Discriminant ∆ = b²-4ac

= (-2√3)²-4(1)(3)

= 12 - 12

= 0

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Answer 2

Given:

The quadratic equation is given x² − 2√3x + 3 = 0

To find:

The value of  b² − 4ac.

Solution:

As we know that in the quadratic equation:  x²-2√3+3 ,  the values of a, b and c are:

a = 1

b = -2√3

c = 3

Therefore, on putting all the values, the value of  b² − 4ac will be:

b² − 4ac = ( -2√3 )^2 - 4*3*1

= 12 - 12

=0

Additional information: b² − 4ac is also known as the discriminant of the quadratic equation and helps to determine various properties of the roots of the quadratic equation.

Therefore the value of   b² − 4ac will be 0.