Math, asked by sukhvansh4, 2 months ago

Obstructive sleep apnea (OSA) is prevalent in 4% of the adult female population. The Berlin Questionnaire will correctly classify people with OSA 81% of the time. However, 20% of the time, the Berlin Questionnaire will incorrectly classify someone without OSA. Suppose you take a random adult female from the population and administer the Berlin Questionnaire. The result indicates the presence of OSA. What is the probability that the random adult female has OSA? (Answer correct to 3 decimal places)​

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Answered by Nirnay155
0

Answer:

For the data of 10 pairs of two random variable X and Y, their means are 68 and 132 respectively and their variances are 64 and 81 respectively . If the sum of products of deviations obtained from their respective means is -576, find r(x,y).

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