Question

obtain a quadratic equation whose roots are -3,-7​

Answer 1

Answer:

3rd quadrant

negative 3 in x axis

negative 7 in y axis.

hope it helps

Answer 2

$\huge\bold{Answer:-}$

Given:-

• The roots of the quadratic equation are -3 , -7

To Find :-

• The quadratic equation .

Solution:-

The sum of the roots = ( α+ β )

= $\dfrac{-b}{a}$

= $\dfrac{Coefficient \:of \:x }{Coefficient \:of \:x²}$

= -3

The product of the roots = ( αβ)

= $\dfrac{c}{a}$

= $\dfrac{Constant \:term}{Coefficient \:of \:x²}$

= -7

Now ,

we know that the formulla to find the quadratic equation is ,

= x² + ( sum of the roots )x - ( products of the roots )

= x² + ( α + β )x - ( αβ )

= x² + [ -3 + (-7 )]x - [ (-3 ) ( -7)]

= x² + [ -10 ]x - [ 21 ]

= x² - 10x - 21

Therefore , The quadratic equation is x² - 10x - 21.