Question

obtain a quadratic equation whose roots are 3
and -10
​

Answer 1

Answer:

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Step-by-step explanation:

If α and β are the roots of a quadratic equation, then the quadratic equation is

${x}^{2} - (α + β)x + α β = 0$

Here, α = 3 and β = -10

Substituting the values of α and β,

we get,

${x}^{2} - (3 - 10)x + 3 \times ( - 10) = 0$

${x}^{2} - ( - 7)x - 30 = 0$

$\bf{x}^{2} + 7x - 30 = 0$