Obtain a quadratic equation whose roots are -3 and -7.
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Answered by
37
Let -3 be alphgussa and -7 be beta
Alpha + beta = -3 + (-7)
= -3-7
= -10
Alpha*beta = -3*-7
= -21
x² - ( alpha + beta )x + alpha* beta = 0
x² + 10x - 21 = 0.
Therefore, The required quadratic equation is x² + 10x - 21 = 0
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Alpha + beta = -3 + (-7)
= -3-7
= -10
Alpha*beta = -3*-7
= -21
x² - ( alpha + beta )x + alpha* beta = 0
x² + 10x - 21 = 0.
Therefore, The required quadratic equation is x² + 10x - 21 = 0
if you are satisfy with my ans then mark me as a brainlist.
if there is something wrong then kindly rectify it
Answered by
5
Answer:
x² + 10x - 21 = 0........
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