Question

obtain a quadratic quation whose roots are -3 and -7 answers

Answer 1

Answer:

(x+3)(x+7)

x²+10x+21

quadratic equation

Answer 2

Answer:

x^2 + 10x + 21

Step-by-step explanation:

Sum of the zeroes = -3 + (-7) = -10

Product of the zeroes = -3 × (-7) = 21

Hence the polynomial formed by the given equation,

= x^2 - (sum of zeroes) x + Product of zeroes

= x^2 - (-10) x + 21

= x^2 + 10x + 21

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