Question

obtain a relation for the distance travelled by an object moving with uniform acceleration in the interval between 4th and 5th second​

Answer 1

Explanation:

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Answer 2

Uniform acceleration in the interval between 4th and 5th seconds =

= (5u + 1/2 * a * 5^2) - (4u + 1/2 * a * 4^2)

= 5u + 1/2 *a * 25 - 4u + 1/2 * a * 16

= u + 1/2 * a * (25-16)

= u + 1/2 * a * 9

= u + 9/2 * a

If it starts from rest then the displacement will be 9/2a.

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