Question

obtain a relation for the distance travelled by an object moving with uniform acceleration in the interval between 4th and 5th second​

Answer 1

Answer:

answer is

Correct option is

A

29×acceleration

From second equation of motion, s=ut+21at2

The displacement after t = 5 seconds will be s5=5u+21a52

The displacement after t = 4 seconds will be s4=4u+21a42

Displacement between 4th and 5th second will be s5−s4=(5u+21a52)−(4u+21a42).

=u+21a(25−16)=u+29a

=29a

my answer is correct mark me brilliant please