obtain all other zero polynomial x^4-5x^3+2x^2+0x-8, √2 and - √2 Dividing the polynomial x^3+5x^2+7x+3 by a polynomial g(x)
q = x+1
R = 0 then
find the g(x)
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Answer:
It is given that 2+
3
,2−
3
are two zeroes of the polynomial f(x)=2x
4
−9x
3
+5x
2
+3x−1
∴(x−(2+
3
))(x−(2−
3
))=(x−2−
3
)(x−2+
3
)
=(x−2)
2
−(
3
)
2
=x
2
−4x+4−3
=x
2
−4x+1
∴(x−(2+
3
))(x−(2−
3
))=x
2
−4x+1 is a factor of f(x)
Now divide f(x) by x
2
−4x+1
∴f(x)=(x
2
−4x+1)(2x
2
−x−1)
Hence, the other two zeroes of f(x) are the zeroes of the polynomial 2x
2
−x−1
2x
2
−x−1=(2x+1)(x−1)
Hence, the other two zeroes are −
2
1
,1.
Explanation:
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