Obtain all other zeroes of 3x^4 + 6x^3 – 2x^2 - 10x – 5, if two of its zeroes are
root 5/3 and - root 5/3.
Step by step explanation.
No , need of unsual answers.
Answers
Answer:
the answer is = -1, -1
Step-by-step explanation:
here ,
two zeros are=root 5/3, -root5/3
so,
3x^4 + 6x^3 – 2x^2 - 10x – 5, divided by (x-root 5/3) and (x+root5/3)
( x-root5/3)(x+root5/3)=x^2-5/3
(3x^4 + 6x^3 – 2x^2 - 10x – 5) / (x^2-5/3)
=3x^2+6x+3
so, (3x^4 + 6x^3 – 2x^2 - 10x – 5) , divided by 3x^2+6x+3
for that,
3x^2+6x+3 =0
=》3x^2+3x+3x+3 =0
=》3x(x+1) + 3(x+1) = 0
=》(x+1) (3x+3) = 0
so,
x= -1 and x= -1
so other zeros are= -1,-1
Step-by-step explanation:
Answer:
Perimeter of rectangle is 136 cm.
Step-by-step explanation:
Given :-
Area of rectangle and area of square are equal.
Perimeter of square is 64 cm.
Breadth of rectangle is 4 cm.
To find :-
Perimeter of rectangle.
Solution :-
• First we will find side of square using perimeter.
• Area of square and area of rectangle are equal. So, then we will find length of rectangle using area of rectangle.
• Then, Finally we will find required perimeter.
________________________________
Perimeter of square = 4 × side
\longrightarrow⟶ 64 = 4 × side
\longrightarrow⟶ 64/4 = side
\longrightarrow⟶ side = 16
Side of square is 16 cm
Area of square = Side × Side
\longrightarrow⟶ Area = 16 × 16
\longrightarrow⟶ Area = 256
Area of square is 256 cm².
It is given that,
Area of rectangle is equal to area of square.
So, Area of rectangle is 256 cm².
Area of rectangle = length × breadth
\longrightarrow⟶ 256 = Length × 4
\longrightarrow⟶ 256/4 = Length
\longrightarrow⟶ Length = 64
Length of rectangle is 64 cm.
Now,
Perimeter of rectangle = 2(Length + Breadth)
\longrightarrow⟶ Perimeter = 2 × (64 + 4)
\longrightarrow⟶ Perimeter = 128 + 8
\longrightarrow⟶ Perimeter = 136
Therefore,
Perimeter of rectangle is 136 cm.