Question

Obtain all other zeroes of 3x4 - 14x2 + 8, if two of its zeroes are √ 2 3 and -√ 2 3

Answer 1

Answer:

3x4-14x2+8

differentiating it wrt x

it becomes

12x3-28x+0

here then,

12x2=28

x2=7/3

x=√7/3&-√7/3.

Answer 2

Answer:

$\huge\star\underline\mathbb{HELLO}$

Other two zeroes are √7/3 & -√7/3

Step-by-step explanation:

3x4-14x2+8

differentiating it wrt x

it becomes

12x3-28x+0

here then,

12x2=28

x2=7/3

x=√7/3&-√7/3.