Question

Obtain all other zeroes of 3x4 + 6x³ 2x²- 10x - 5 if two of its zeroes are √(5/3) and -√(5/3).

Please help me today is my paper ​

Answer 1

Answer:

-1,-1,√(5/3) and -√(5/3) are the zeros

Step-by-step explanation:

Two zeros are √(5/3) and -√(5/3)

so we can write it ad x=√(5/3) and x= -√(5/3)

we get x-√(5/3) =0andx +√(5/3)=0

multiply bothe the factors we get,

x²-5/3=0

multiply by 3 we get,

3x²-5=0 is the factor of 3x⁴+6x³-2x²-10x-5=0

now divide it by 3x²-5=0 we get,

x²+2x+1=0

x²-(sum of root)x + (product of root)=0

sum of root = 2

product=1

so we get

x²+x+x+1=0

x(x+1)+1(x+1)=0

x+1=0,x+1=0

x=-1 ,x=-1

so the zeros are -1,-1,√(5/3) and -√(5/3)