Obtain all other zeroes of the polynomial x
4 - 3√2 x3+ 3√2 x -4 if two of its zeroes are √2 and
2√2.
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Step-by-step explanation:
Solution :- given
⇒P(x)=x4−32x3+3x2+32x−4=0
as Two zero is given 2,22
∴(x−2)(x−22)=x2−32x+4
Now considering a standard quadratic equation
ax2+bx+c=0
We can say
(x2−32x+4)(ax2+bx+c)=p(x)
⇒ax4−3a2x3+4ax2+bx3−3b2x2+4bx+cx2−3c2x+4c=p(x)
⇒ax4
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