obtain all other zeros of the polynomial x^4+2x^3-13x^2- 38x-24 if two of its zeros are -1 and -2
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Hi friend,
Here's ur solution -
Let, p(x)= x⁴+2x³-13x²-38x-24
Since, -1 and -2 are the two zeros of the polynomial.
(x+1)(x+2) = x²+2x+x+2
g(x)= x²+3x+2
On dividing p(x) by g(x).
We get ,
q(x)=x²-x-12
= x²-4x+3x-12
=x(x-4)+3(x-4)
=(x-4)(x+3)
One of the zero is 4 and other zero is -3.
Also , -2 and -1 are the given zeros
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