Question

Obtain all other zeros of x4-8x3
+23x2-28x+12 if two of the zeros are 1
and 2​

Answer 1

Step-by-step explanation:

${x}^{4} - 8 {x^{3} } + 23 {x}^{2} - 28x + 12 = 1 - 8 + 23 - 28 + 12 = 0 = 16 - 64 + 23 \times 4 - 28 \times 2 + 12 = 16 - 64 + 92 - 56 + 12 = - 52 + 92 - 44 = 0$